求助一个正则匹配式（Perl 风格)

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http://schema.3360sz.net/public/LoadSchema.aspx?id=20201130669

获取到后面的 id

我写的是

/http?:\/\/schema\.3360sz\.net\/public\/LoadSchema.aspx?id=([0-9]+)/

输出是 null...,来回修改 N 次都是把握不到 Perl 风格的精髓。。。囧。。。
感谢感谢！！！

4 replies • 2020-11-30 21:53:48 +08:00

rrfeng

Nov 30, 2020

https://regex101.com/

https?:\/\/schema\.3360sz\.net\/public\/LoadSchema\.aspx\?id=(\d+)

rrfeng

Nov 30, 2020

https://regex101.com/

https?:\/\/schema\.3360sz\.net\/public\/LoadSchema\.aspx\?id=(\d+)

lution

Nov 30, 2020

https?:\/\/schema\.3360sz\.net\/public\/LoadSchema\.aspx\?id=([0-9]+)

lution

Nov 30, 2020

本来也想推荐 regex 给楼主，命中 spam 规则死活发不出来。。。

yangyaofei

Nov 30, 2020 via Android

直接 id= 分字符串不好么………