js 树向上递归修改数据有什么好的写法呢！

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let a = [
  {
    key: 1,
    title: '一级',
    parentKey: 0,
    status: {choose: false},
    children: [
      {
        key: 10, title: '一级-0', parentKey: 1, status: {choose: false}, children: [
          {key: 15, title: '一级-0-1', parentKey: 10, status: {choose: false}}
        ]
      },
      {key: 11, title: '一级-1', parentKey: 1, status: {choose: false}},
      {key: 12, title: '一级-2', parentKey: 1, status: {choose: false}},
      {key: 13, title: '一级-3', parentKey: 1, status: {choose: false}},
      {key: 14, title: '一级-4', parentKey: 1, status: {choose: false}}
    ]
  }
];

我想修改 key 15 每个父级 status 里的 choose 状态。也就是 key 10 key 的 status choose 都为 true 如果是 json 对象很好找，但是已经是树形了向下好找却向上不好找！怎么更优的实现它呢！

11 replies • 2019-09-19 15:06:25 +08:00

lemontv

Sep 19, 2019 via Android

直接判断当前节点的子节点是否包括 key15

azh7138m

Sep 19, 2019

提前把祖先存下来呗

https://runkit.com/muzea/5d826fe387ee180014a5d330

autoxbc

Sep 19, 2019

把对象展平就很容易寻址

https://codepen.io/autoxbc/pen/xxKyWmq

coderabbit

Sep 19, 2019

```
let parent = (data, obj) => {
data.forEach(item => {
if (item.key === obj.parentKey) {
item.status.choose = true;
parent(data, item);
}
if (item.children && item.children.length) {
item.status.choose = true;
parent(item.children, obj);
}
});
};
let obj = { key: 15, title: '一级-0-1', parentKey: 10, status: { choose: false } };
console.log(a);
```

coderabbit

Sep 19, 2019

@autoxbc @azh7138m 学习了