ss=re.findall(u' (\d+)小时前',s) ss [] s ' · 6 小时前'
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Supplement 1 · Jul 28, 2018
for i in range(1,10):
s.append(i)
s
[1, 2, 3, 4, 5, 6, 7, 8, 9]
for i in range(-1,-3):
s.remove(s[i])
s
[1, 2, 3, 4, 5, 6, 7, 8, 9]
s.append(i)
s
[1, 2, 3, 4, 5, 6, 7, 8, 9]
for i in range(-1,-3):
s.remove(s[i])
s
[1, 2, 3, 4, 5, 6, 7, 8, 9]
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