把数组中的值变为键名，求解

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array(6) {
[0]=>
string(3) "111"
[1]=>
string(3) "222"
[2]=>
string(3) "333"
[3]=>
string(3) "444"
[4]=>
string(3) "555"
[5]=>
string(3) "666"
}

现在想得到：
array(6) {
[111]=>
string(3) "222"
[333]=>
string(3) "444"
[555]=>
string(3) "666"
}

string

array

键名

求解

6 replies • 2017-10-08 11:18:50 +08:00

cnqncom

Oct 8, 2017

array(3) {
[111]=>
string(3) "222"
[333]=>
string(3) "444"
[555]=>
string(3) "666"
}

zcc911

Oct 8, 2017

最简单的：
$arr = ['111', '222', '333', '444', '555', '666'];
$arr_out = [];
for($i = 0; $i < count($arr); $i+=2){
$arr_out["{$arr[$i]}"] = "{$arr[$i+1]}";
}
echo "<pre>";
var_dump($arr_out);
echo "</pre>";

VgV

Oct 8, 2017

试试 array_flip($array);

VgV

Oct 8, 2017

哦，刚才没注意看，我还以为是把值改为名呢。
你下面想得到的结果是必须借用循环来排序了，没有更简单的了。

cnqncom

Oct 8, 2017

感谢各位

lujjjh

Oct 8, 2017

$pairs = array_chunk(['111', '222', '333', '444', '555', '666'], 2);
$keys = array_column($pairs, 0);
$values = array_column($pairs, 1);
$result = array_combine($keys, $values);

print_r($result);