比如像这样的地址用 urllib.request 获取时会报错
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ltuxMay 5, 2017
1
[urllib.quote()]( https://docs.python.org/2/library/urllib.html#urllib.quote)
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noe132May 5, 2017
2
unicode 字符应该是要编码成类似%20%20 这样的东西
先把 url 给 encode 一下应该就可以了。 urllib.urlencode(url) |
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golmicMay 5, 2017
3
用 requests
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owt5008137May 5, 2017 via Android
4
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