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flask route()能否加载动态网页?
iphantom
·
Jun 14, 2016
· 3383 views
This topic created in 3801 days ago, the information mentioned may be changed or developed.
route(/getname) 可以
route(/getname?abc) 不可以
求教解决办法·······
Route
getname
flask
abc
5 replies
•
2016-06-14 12:57:11 +08:00
am241
Jun 14, 2016 via Android
1
参数不应该在程序里判断的吗
iphantom
OP
Jun 14, 2016
2
@
am241
什么意思
https://127.0.0.1:5000/Assess/getPriceByKeyWord?access_token=xxxx&sCity=xxxx&sKeyWord=xxxx&sUserKey=xxxx
这样的链接 返回一个固定的值 怎么实现?
seki
Jun 14, 2016
3
问号后是参数
http://flask.pocoo.org/docs/0.11/quickstart/#accessing-request-data
iphantom
OP
Jun 14, 2016
4
找到原因了 https http
哎 郁闷
daweibao
Jun 14, 2016 via Android
5
route(/getname/<string:name>)
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